## The Electric Field of a DipoleIn this lab we will investigate the electric field of a dipole configuration and calculate the charge of the dipole itself.
We know that the electric field due to a single charge is kq/r From electrostatic theory we can calculate that at distances much greater than separation of the dipole charges the electric field is given by:
We also know that for small distances (d), we can claim that
In this lab we will determine the electric fields and with that information find the charge of the dipole (the total charge will be zero because it is made up of two equal but opposite charges, but by convention we refer to the charge of dipole as the value on the positive charge). We can define 3 cos ^{2} θ - 1 as X1 and Sin(2θ) as X2, and this will given us E_{x} as
a linear function of X1 and E_{y} as a linear function of X2. How does this help? If we use
X1 as our variable then we can plot E_{x} on the y-axis and X1 on the x-axis and we should
get a straight line. The slope of that line can reveal information about the charge on the
dipole.
2. Connect the wired pins to the power supply (red positive, black negative). Use the DMM to set the output voltage to about 20V. Do not change the voltage for the rest of the experiment. 3. Push the pins into the center of each electrode spot on the dipole sheet.
4. Start collecting data in Microsoft Excel. You should have four columns. The first
column should be labeled point, the second X1, the third V 5. Go to point 1 on the corner of the dipole sheet marked X-Component. Use the probes to measure the voltage. The tips of the probes should straddle the point marked on your paper. Make sure you measure in the X direction and not the Y direction! 6. In your table, this corresponds to point 1. X1 has a value of -1 (at point 1 θ is at 90, hence the value of the cosine function is zero, this is why X1 is -1 at point 1). X1 increases by steps of 0.3, so X1 will be -0.7 for the second entry. Vx is whatever value you just measured. Ex is simply Vx divided by the spacing of the probe tips (10.3mm). 7. Repeat until you have completed all 11 points in the X section. 8. Do the same for the Y section of the paper, this time being careful to measure in the Y direction. In your lab notebook, plug in the initial and final angles and argue that the values of the X2 variable will run from 0 to 1 in increments of 0.1.
Under the Chart menu, click on "Add Trendline". For options you want to display the equation and the R-squared value. This will put a least-squares fit on your graph and give the slope. The R-squared number should be close to one. If it is not, it means that some of your data may be non-linear. Note that if your R-squared number is equal to one, this often is a sign that you have made some kind of error as it implies straight-line data with no "noise". From the slope you can go back and calculate the charge. Note that
E
Therefore the slope of the E
Repeat this process for E At this point you will have two values for Q, they should be the same (we have measured the same physical quantity in two different ways). Because no measurement is perfect, these numbers will differ. Can we claim that within the uncertainty of measurement that these two numbers are the same? Here we need to use some error-analysis tools we learned in the first lab. Before you do the next step, save your data and graphs. Excel is a little quirky, and can freeze while using the following function. So make sure that you don't have to redo all of your work.
We derived Q from the slope of the graph, what's the uncertainty in that slope? Excel
can tell us! We will use the LINEST feature in Excel. Go to an empty cell in Excel and
type The next question is "given the uncertainty on the slope, how do we calculate the uncertainty in Q?" Take the uncertainty in the slope and divide it by the slope, that gives the percentage error of the slope. Since Q is the product of a constant times the slope, the percentage uncertainty in Q is the same as the percentage uncertainty in the slope. So the actual uncertainty in Q is Q itself multiplied by the percentage uncertainty. So we should now have two values of Q and each will have an uncertainty associated with it. Again, ideally the value of Q from the x measurements should be the same as the value of Q derived from the y measurements. Hence the difference between these two results should be zero. Of course, since these are experimental measurements, the difference between the two will be non-zero, but the difference should also be within the uncertainty of our measurements. First check to see if the difference is smaller than the larger of your two uncertainties. If it is, then the values of Q are smaller than the uncertainty involved, and you have shown that the two methods give the same value of Q. If your difference in Qs is larger than the bigger uncertainty, then you will have to add the two uncertainties. How do we add uncertainties? As it turns out, we add them like Pythagoras. Square each, add, then take the square root. Hopefully your difference will be smaller than this number, if not your conclusion should explain why not. In your conclusion discuss what you have learned about the electric fields and how well your Q values agreed. If they were outside the limits suggested by their uncertainties, provide some explanations. Remember that "human error" is not an explanation. |